x^2+14x+35=4

Solution for x^2+14x+35=4 equation:

x^2+14x+35=4

We move all terms to the left:

x^2+14x+35-(4)=0

We add all the numbers together, and all the variables

x^2+14x+31=0

a = 1; b = 14; c = +31;
Δ = b2-4ac
Δ = 142-4·1·31
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6\sqrt{2}}{2*1}=\frac{-14-6\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6\sqrt{2}}{2*1}=\frac{-14+6\sqrt{2}}{2}
$